Six capacitors and their specification are 1, 1/2, 1/3, 1/4, 1/5 and 1/6F respectively. And only one of them is different from its specification. Given an ideal battery, several light bulbs and sufficient wires, you need to find out the special one. Each bulb can only be lighted up once before it is destroyed. Assume that the brightness=Voltage*Capacity, that is equal to the volume of electricity in the capacitor. And you can compare the brightness.
1. At least how many bulbs do you need to be sure to find out the special capacitor?
2. What if there are 5 capacitors? and the smallest one is 1/5F.
3. What if there are 4 capacitors? and the smallest one is 1/4F.
4. What if there are 3 capacitors? and the smallest one is 1/3F.
----Designed by Hansen Chen in 2010( http://wiki.sdn.sap.com/wiki/display/SCNPC/Home )